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For an equilibrium reaction, the rate co...

For an equilibrium reaction, the rate constants for the forward and the backward reaction are `2.38xx10^(-4)` and `8.15xx10^(-5)`, respectively. Calculate the equilibrium constant for the reaction.

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The correct Answer is:
`2.92`
`K=(K_(f))/(K_(b)) =(2.38xx 10^(-4))/(8.15 xx 10^(-5)) =2.92`
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