At 500 K, equlibrium constant, `K_(c)` for the following reaction is 5.
`1//2 H_(2)(g)+ 1//2(g)hArr HI (g)`
What would be the equilibrium constant `K_(c)` for the reaction `2hi(g)hArrH_(2)(g)+l_(2)(g)`

Options

A. 0.04
B. 0.4
C. 25
D. 2.5

Answer

A

Explanation

For the reaction,
`1//2H_(2)(g)+1//2 I_(2)(g)hArrHI(g),K_(c)=5`
For the reaction,
`HI(g)hArr1//2H_(2)(g)+1//2l_(2)(g),K_(c)=(1)/(5)`
For the reaction
`2HI(g)hArrH_(2)(g)+l_(2)(g),K_(c)=((1)/(5))^(1//2)`