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OSTWALD'S DILUTION LAW

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Ostwald Dilution Law

Question based on Ostwald Dilution Law | Le Chatelier Principle | Density based Concept

The strength of elctrolytes is expressed in terms of degree of dissociation alpha For strong electrolyte alpha is close to one and for weak electrolytes alpha is quite small. According to Ostwald Dilution Law alpha=sqrt((K)/(C)) For an acid [H^(+)] = sqrt(K_(a)C) For a base [OH^(-)] =sqrt(K_(b)C The relative strengths of acids or bases can be compared in terms of the square roots of their K_(a) " or " K_(b) values. A monoprotic acid in 0.1 M solution ionises to 0.001 % . Its ionisation constant is :

Leveling Effect OF water Weak and Strong Electrolytes|| Arhenius Theory OF Electrolytic Dissociation|| Ostwald's Law

The dissociation of weak electrolyte (a weak base or weak acid) is expressed in terms of Ostwald's dilution law. An acid is substance which furnishes a proton or accepts an electron pair, where a base is proton acceptor or electron pair donor. Stronger is acid, weaker is its conjugate base. The dissociation constants of an acid (K_(a)) and its conjugate base (K_(b)) are related by K_(w)=K_(a)xxK_(b) , where K_(w) is ionic product of water equal to 10^(-14) at 25^(@)C . The numerical value of K_(w) however increase with temperature. In a solution of an acid or base [H^(+)][OH^(-)]=10^(-14) . Thus the [H^(+)] in a solution is expressed as: [H^(+)]=10^(-pH) and pH+pOH=14 . Buffer solution are the solutions which do not show appreciable change in the pH on addition of small amount of acid or base. The pH of II gp. filtrate during III gp. basic radicals precipitation in qualitative anlysis is maintained by using a buffer solution of:

Determination OF Relative Lowering by Ostwald Walker Method || Elevation in Boiling Point

The degree of dissociation of weak electrolyde is inversely proportional to the square root fo concentration. It is called Ostwald's dilution law. alpha = sqrt((K_(a))/(c)) As the tempertaure increases, degree of dissociation will increase. (alpha_(1))/(alpha_(2)) = sqrt((K_(a_(1)))/(K_(a_(2)))) if concentration is same. (alpha_(1))/(alpha_(2)) = sqrt((c_(2))/(c_(1))) if acid is same. pH of 0.005 M HCOOH [K_(a) = 2 xx 10^(-4)] is equal to

The degree of dissociation of weak electrolyde is inversely proportional to the square root fo concentration. It is called Ostwald's dilution law. alpha = sqrt((K_(a))/(c)) As the tempertaure increases, degree of dissociation will increase. (alpha_(1))/(alpha_(2)) = sqrt((K_(a_(1)))/(K_(a_(2)))) if concentration is same. (alpha_(1))/(alpha_(2)) = sqrt((c_(2))/(c_(1))) if acid is same. 0.01M CH_(3)COOH has 4.24% degree of dissociation, the degree of dissociation of 0.1M CH_(3)COOH will be

DINESH PUBLICATION-EQUILIBRIUM-Short Answer Question
  1. In a gaseous reaction , the reactant moles are more than the product m...

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  2. An inert gas does not alter the state of chemical equilibrium when add...

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  3. What is an electrolyte ? How are electrolytes classified ?

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  4. OSTWALD'S DILUTION LAW

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  5. All Arrhenius acids are Bronsted acids but all Arrhenius bases are not...

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  6. Discuss two limitations of Arrhenius theory .

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  7. Relative strangths of weak acids and weak bases are compared in terms...

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  8. What are conjugate acid base pairs. Give two examples.

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  9. Select the conjugate pairs in the following reactions: HCI + HCO(3)^...

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  10. Even ions can act as acids and bases. State the concept which accounts...

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  11. Predict whether the following substance will give , acidic, basic or n...

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  12. Write the conjugate base of the following : " (i) " NH(3) " (ii) " ...

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  13. Explain ionic product of water . What is the effect of temperature on ...

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  14. The nature of a solution can be expressed in terms of its [H(3)O^(+)]....

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  15. Explain the term pH of a solution . What is pH of blood ?

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  16. How can you calculate the pH of a buffer soluiton ? Write the mathem...

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  17. Identify the acid-base pair in the following reaction : HSO(4)^(-) ...

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  18. COMMON ION EFFECT

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  19. DIFFERENCE BETWEEN IONIC PRODUCT AND SOLUBILITY PRODUCT

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  20. When HCI gas is passed through the saturated solution of impure sodium...

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