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The [Ag^(+)] =10^(-5) in a solution . Th...

The `[Ag^(+)] =10^(-5)` in a solution . The `[CI^(-)]` to precipitate `AgCI (K_(sp) " of " AgCI =2 xx 10^(-12))` is :

A

`10^(-5)`

B

`10^(-7)`

C

`10^(-8)`

D

`10^(-9)`

Text Solution

Verified by Experts

The correct Answer is:
A
`[CI^(-)] =(K_(sp))/([Ag^(+)]] = (2xx 10^(-12))/(10^(-5))`
Thus `[CI^(-)]` must be more than `10^(-7)`
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