The solubility product of a sparingly soluble salt `AX_(2)` is `3.2xx10^(-11)`. Its solubility (in `mo//L`) is

Options

A. `5.6 xx 10^(-6)`
B. `3.1 xx 10^(-4)`
C. `2xx 10^(-4)`
D. `4xx 10^(-4)`

Answer

C

Explanation

`AX_(2) hArr underset(S)(A^(2+)) + underset(2S)(2X^(-))`
`K_(sp) =4S^(3) " or " S =((K_(sp))/(4))^(1//3)`
`S=((3.2xx 10^(-11))/(4)) ^(1//3)`
`=(8 xx 10^(-12))^(1//3) =2xx 10^(-4)`