the value of equilibrium constant for the reaction
`HI(g) hArr 1//2 H_(2) (g) +1//2 I_(2) (g) " is " 8.0`
The equilibrium constant for the reaction
`H_(2) (g) +I_(2) (g) hArr 2HI(g)` will be

Options

A. 16
B. `1//8`
C. `1//16`
D. `1//64`

Answer

D

Explanation

`HI(g) hArr 1//2 H_(2) (g) + 1//2I_(2) (g)`
`K= [[H_(2)]^(1//2) [I_(2)]^ (1//2)]/[[HI]] =8`
`H_(2)(g) +I_(2) (g) hArr 2HI(g)`
`K =[[H]^(2)]/[[H_(2)][I_(2)]] =((1)/(8))^(2) =(1)/(64)`