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The pK(a) of HCN is 9.30. The pH of a so...

The `pK_(a)` of `HCN` is 9.30. The pH of a solutin prepared by mixing `2.5` moles of `KCN` and `2.5` moles of `HCN` in water and making up the total volume to `500 mL` is

A

`9.30`

B

`7.30`

C

`10.30`

D

`8.30`

Text Solution

Verified by Experts

The correct Answer is:
A
In the Henderson's equation
`pH =pK_(1) + " log " .[["salt"]]/[["Acid"]]`
`" When "["Salt"] = ["Acid"]`
`pH =pK_(a) =9.30`
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