One "mole" of `N_(2)O_(4)(g)` at `300 K` is kept in a closed container under `1` atm. It is heated to `600 K`, when `20%` by mass of `N_(2)O_(4)(g)` decomposes to `NO_(2)(g)`. The resultant pressure is

Options

A. `1.2 atm`
B. `2.4`atm
C. `2.0` atm
D. `1.0` atm

Answer

B

Explanation

`{:(N_(2)O_(4) ,harr, 2NO_(2)),(1,,0),(1-0.2,,0.4),(=0.8,,):}`
Number of moles at 300K=1
No. of moles at 600K =0.8 +0.4 =1.2
`:.` V is constant
`:. (p_(2))/(p_(1)) =(n_(2)T_(2))/(n_(1)T_(1)) (P_(2))/(1)=(1.2xx 600)/(1xx300) =2.4 " atm "`