Consider the following equilibrium in a closed container
`N_(2)O_(4)(g) hArr 2NO_(2)(g)`
At a fixed temperature, the volume of the reaction container is halved. For this change, which of the following statement holds true regarding the equilibrium constant `(K_(p))` and the degree of dissociation `(alpha)`?

Options

A. Neither `K_(p) " nor " alpha` changes
B. Both `K_(p) " and "alpha` change
C. `K_(p)` changes but `alpha` does not change
D. `K_(p)` does not change order of solubility of :

Answer

D

Explanation

When volume is dicreased. Pressure increases and this will favour bacward reaction. Thus degree of dissociation decreases but `K_(p).` does not change since temp. is constat.