Home
Class 11
CHEMISTRY
A student performs a titration with diff...

A student performs a titration with different burettes and find titre values of `25.2 mL, 25.25 mL and 25.0 mL`. What is the average titre value based upon rounded off principle ?

Text Solution

Verified by Experts

Average titre value `= ((25.2+25.25+25.0))/(3)mL=25.15mL`
The maximum number of significant figures to be reported is three (3). This means that the last digit 5 has to be dropped and the correct answer is 25.2 mL based on rule-3.
Promotional Banner

Topper's Solved these Questions

  • MOLE CONCEPT

    DINESH PUBLICATION|Exercise Board Examinations|35 Videos
  • MOLE CONCEPT

    DINESH PUBLICATION|Exercise N.C.E.R.T (Short answer)|13 Videos
  • HYDROGEN

    DINESH PUBLICATION|Exercise LONG|1 Videos
  • NOMENCLATURE OF ORGANIC COMPOUNDS

    DINESH PUBLICATION|Exercise MCQs|13 Videos

Similar Questions

Explore conceptually related problems

The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If correct answers to the question number A,B,C and D (say) are 4,0,9 and 2 respectively, then correct darkening of bubbles should be as shown on the side. (B) A student performs a titration with different buretters and finds titre values of 25.2 mL, 25.25 mL and 25.0 mL. The number of significant figures in the average titre value is ........

A student of performs a titration with different burettes and finds titre values of 25.2 mL , 25.25 mL , and 25.0 mL . The number of significant figures in the average titre value is …..

If a=25 ,then find the value of a^(25^(0))+a^(0^(25)) .

10.0mL of Na_2CO_3 solution is titrated against 0.2M HCl solution. The following titre values were obtained in 5 readings : 4.8mL, 4.9mL, 5.0mL, 5.0mL, and 5.0mL Based on these readings, and convention of titrametric estimation the concentration of Na_2CO_3 solution is.........nM. (Round off to the Nearest Integer).

The decompoistion of H_(2)O_(2) can be followed by titration with KMnO_(4) and is found to be a first order reaction. The rate constant is 4.5 xx 10^(-2) . In an experiment, the initial titre value as 25 mL . The titre value will be 5 mL after a lapse of