What weight of sodium cloride decomposed by `4.9 g` of sulphuric acid, if 6 g of sodium hydrogen sulphide `(NaHSO_(4))` and `1.825 g` of hydrogen chloride are produced in the same reaction ?

Explanation

The chemical equation for the reaction is :
`NaCl+H_(2)SO_(4)rarrNaHSO_(4)+HCl`
Weight of the reaction = Weight of NaCl + Weight of `H_(2)SO_(4)`
`= x = 4.9 g`
(Here `x` is the weight of `NaCl`)
Weight of products = Weight of `NaHSO_(4)+` Weight of `HCl`
`= 6.0 g+ 1.825 g = 7.825 g`
Now, according to law of conservation of mass
Weight of reaction = Weight of products
`x=4.9=7.825,x=7.825-4.9=2.925g`
`:.` Weight of `NaCl` decomposed `= 2.925 g`.