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Copper gives two oxides. On heating 1g o...

Copper gives two oxides. On heating `1g` of each in hydrogen, we get `0.888 g and 0.798 g` of the metal respectively. Show that these results are in agreement with the Law of Multiple Proportions.

Text Solution

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Let us fix `1g` of copper as the fixed weight in the two oxides
In the first oxide
Weight of copper `= 0.888 g`
Weight of oxygen `= 1-0.888 = 0.112g`
Now, `0.888g` of copper combine with oxygen `= 0.112 g`
`:. 1.0 g` of copper combine with oxygen `= (0.112)/(0.888)g=0.126 g`
In the second oxide
Weight of copper `= 0.798 g`
Weight of oxygen `= 1-0.798 = 0.202 g`
`0.798 g` of copper combine with oxygen `=0.202 g`
`1.0 g` of copper combine with oxygen `= (0.202)/(0.798)g=0.253 g`
Ratio by weight of oxygen which combine with `1g` of copper in the two oxides is `0.126 : 0.253 or 1:2` As the ratio is simple whole number in nature, the law of Multiple Proportions is proved.
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