How many atoms of each type present in 143 g of washing soda `(Na_(2)CO_(3).10H_(2)O)` ?

Explanation

To find out how many atoms of each type are present in 143 g of washing soda (Na₂CO₃·10H₂O), we will follow these steps:

### Step 1: Calculate the molar mass of washing soda (Na₂CO₃·10H₂O)

- Sodium (Na): 23 g/mol, and there are 2 sodium atoms → 2 × 23 = 46 g/mol
- Carbon (C): 12 g/mol → 12 g/mol
- Oxygen (O) in carbonate (CO₃): 3 × 16 = 48 g/mol
- Water (H₂O): 18 g/mol, and there are 10 water molecules → 10 × 18 = 180 g/mol
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