A cylinder of compressed gas contains nitrogen and oxygen in the molar ratio of `3:1`. If the cylinder contains `2.5 xx 10^(4)g` of oxygen, what is the total mass of the gas in the mixture ?

Explanation

Number of moles of oxygen `= ("Mass of oxygen")/("Molar mass of oxygen")=((2.5xx10^(4)g))/((32.0" g mol"^(-1)))=781.25` mol
Number of mass of nitrogen `= 3xx781.25=2343.75` mol
Mass of nitrogen `= (2343.75 " mol")xx(28 " g mol"^(-1))`
`=65625g=6.5625xx10^(4)`g
Total mass of gas (oxygen + nitrogen) `= (2.5 xx 10^(4)+6.5625xx10^(4)g)=9.0625xx10^(4)g`.