What weight of calcium the same number of atoms as are present in 3.2g of sulphur ?

Explanation

Step I : No. of atoms in 3.2 g of sulphur
Gram atomic mass of `S = 32` g
32 g of sulphur atoms `= 6.022 xx 10^(23)`
3.2 g of sulphur contain atoms `= (6.022xx10^(23))/((32g))xx(3.2g)=6.022xx10^(22)`
Step II. Weight of `6.022 xx 10^(22)` atoms of calcium
Gram atomic mass of Ca = 40 g
`6.022 xx 10^(23)` atoms of Ca weigh = 40 g
`6.022 xx 10^(22)` atoms of Ca weigh `= ((40g))/(6.022xx10^(23))xx6.022xx10^(22)=4g`.