How much copper can be obtained from `100g` of copper sulphate `(CuSO_(4))`?

Explanation

Molecular mass of `CuSO_(4)` = Atomic mass of Cu + Atomic mass of `S + 4 xx` Atomic mass of O
`= 63.5 +32 +4 xx 16 = 159.5` u
Gram molecular mass of `CuSO_(4)=159.5` g
Now, `159.5 g` of `CuSO_(4)` have Cu = 63.5 g
`:.` 100 g of `CuSO_(4)` have `Cu = (63.5 g)xx((100g))/((159.5 g))=39.81 g`.