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How many moles of methane are required t...

How many moles of methane are required to produce 22g of `CO_(2)` on combustion ?

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The balanced equation for the combustion reaction is :
`underset("1 mol")(CH_(4)(g))+2O_(3)(g)rarrunderset("1 mol")(CO_(2)(g))+2H_(2)O(l)`
No. of moles in 22 g of `CO_(2)=("Mass of "CO_(2))/("Molar mass")=((22g))/((44"g mol"^(-1)))=0.5` mol
1 mole of `CO_(2)` is produced from methane = 1 mol
0.5 mole of `CO_(2)` is produced from methane = 0.5 mol.
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