1 gm of a mixture of calcium carbonate and magnesium carbonate gave on ignition 240 mL of carbon dioxide at S.T.P. What is the percentage composition of the mixture ?

Explanation

To solve the problem of determining the percentage composition of a mixture of calcium carbonate (CaCO3) and magnesium carbonate (MgCO3) that produced 240 mL of carbon dioxide (CO2) upon ignition, we can follow these steps:

### Step 1: Define Variables
Let:
- \( x \) = mass of calcium carbonate (CaCO3) in grams
- \( 1 - x \) = mass of magnesium carbonate (MgCO3) in grams (since the total mass of the mixture is 1 gram)

### Step 2: Calculate CO2 Production from CaCO3
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