Concentrated aqueous solution of sulphuric acid is `98 %` by mas and has density of `1.80 "g mL"^(-1)`. What is the volume of acid requird to male one litre `0.1 M H_(2)SO_(4)` solution ?

Explanation

Volume of 98 % by mass of `H_(2)SO_(4)=("Mass")/("Density")=((100g))/((1.80"g mL"^(-1)))`
`=55.55mL=0.0555L`
Molarity of solution `(M)=("Mass of "H_(2)SO_(4)//"Molar mass")/("Volume of solution in litres")`
`=((98.0g)//(98.0"g mol"^(-1)))/((0.0555L))=18.02 "molL"^(-1)=18.02`
Volume of solution required to make 1L of `0.1 M H_(2)SO_(4)` solution
`M_(1) V_(1) -= M_(2)V_(2)`
`(18.02M)xxV_(1)=(0.1 M)xx(1.0 L)`
`V_(1)=((0.1M)xx(1.0L))/((18.02M))=0.0055L=5.5mL`.