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In a reaction vessel, 0.184 g of NaOH is...

In a reaction vessel, 0.184 g of NaOH is required to be added for completing the reaction. How many millilitres of 0.150 M NaOH solution should be added for this reaction ?

Text Solution

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Mass of NaOH = 0.184 g , Molar mass of NaOH `= 40.0 "g mol"^(-1)`
Molarity of solution `= 0.150 M = 0.15 mol L^(-1)`
Let the volume of solution = V mL
Now, Molarity of solution (M) `= ("Mass of NaOH/Molar mass")/("Volume of solution")`
`(0.15 "mol L"^(-1))=((0.184g))/((40.0"g mol"^(-1))xx"Volume of solution")`
`:.` Volume of solution `= ((0.184g))/((0.15 "mol L"^(-1))xx(40 "g mol"^(-1)))=0.0307L=30.7 mL`.
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