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The density of 3 molal solution of NaOH ...

The density of 3 molal solution of NaOH is 1.110g `mL^(-1)`. Calculate the molarity of the solution.

Text Solution

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3 molal NaOH solution represents 3 moles of solute dissolved in 1000 g of water
Mass of the solution = (Mass of the solute)+(Mass of the solvent)
`=(3 mol xx 4 g mol^(-1))+(1000g)`
`=120g + 1000g = 1120 g`
Volume of the solution `= ("Mass")/("Density")=(1120 g)/((1.110 "g mL"^(-1)))=1009 mL`
Molarity of the solution `(M)=("Moles of the solution")/("Volume of the solution in litres")=((3mol))/((1009//1000L))=2.97"mol L"^(-1)=2.97M`
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