How many oxygen are present in 96 g of ozone ?

Explanation

Gram molecular mass of `O_(3)=48 "g mol"^(-1)`
No. of moles of ozone `(O_(3))` in 96 g `= ((96 g))/((48"g mol"^(-1)))=2mol`
1 mole of ozone has oxygen atoms `= 3 "mol" = 3 xx N_(A)`
2 mole of ozone has oxygen atoms `= 6 xx N_(A) = 6 xx 6.022 xx 10^(23)`
`=3.612 xx 10^(24)` atoms.