When 6.3 g of `NaHCO_(3)` (sodium bicarbonate) is added to a solution of `CH_(3)COOH` (acetic acid) weighing 15 g, it is observed that `3.3 g CO_(2)` is released to the atmosphere. The residue is found to weigh 18.0 g. Show that the data is in agreement with the law of conservation of mass.

Explanation

The chemical equation for the reaction is :
`NaHCO_(3)+CH_(2)COOHrarrCH_(3)COONa+H_(2)O+CO_(2)`
Sod. Bicarbonate Acetic acid `underset(("Residue"))(underbrace("Sod. acetate"))`
Mass of reactants = Mass of `NaHCO_(3) + "Mass of "CH_(3)COOH = 6.3 + 15 = 21.3 g`
Mass of product = Mass of residue + Mass of `CO_(2)=18 + 3.3 = 21.3 g`
Since these is no change in mass during the chemical reaction the data illustrates the Law of conservation of Mass.