If law of constant composition is true, what weights of calcium, carbon and oxygen are present in 1.5 g of calcium carbonate ? Given that the sample of calcium carbonate from another sample contains Ca = 40.0 %, C = 12.0 % and O = 48.0 %

Answer

Wt. of Ca = 0.6 g ; C = 0.18 g ; O = 0.72 g

Explanation

Since the Law of Constant Composition is true, the ratio by weight of the elements in the two samples of `CaCO_(3)` must be the same
Weight of `Ca=((1.5g)xx40)/(100)=0.6g` , Weight of C `=((1.5g)xx12)/(100)=1.18g`
and Weight of `O=((1.5g)xx48)/(100)=0.72g`.