Hydrogen peroxide and water contain 5.93 % and 11.2 % of hydrogen respectively. Show that the data illustrates the law of multiple proportions.

Explanation

In `H_(2)O_(2)`
Percentage of `H = 5.93`
Percentage of `O = 100 - 5.93 = 94.07`
5.93 g of hydrogen are combined with oxygen = 94.07 g
1.0 g of hydrogen is combined with oxygen `= (94.07)/(5.93) g = 15.86 g`
In `H_(2)O`
Percentage of `H = 11.2`
Percentage of `O = 100 - 11.2 = 88.8 `
11.2 g of hydrogen are combined with oxygen = 88.8 g
1.0 g of hydrogen is combined with oxygen `= (88.8)/(11.2)g =7.93 g`
Ratio by weights of oxygen combining with 1.0gram of hydrogen in the two oxides is 15.86 : 7.93 or 2 : 1
Since it is a simple whole number ratio, the data is according to Law of Multiple proportions.