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0.14 g of an element A combines with 0.1...

0.14 g of an element A combines with 0.16 g of the elements B. Also 0.05 g of another element C combines with 0.35 g of A. It was also found that 0.2857 g of C combines with 2.2857 g of B. Show that the data illutrates the law of reciprocal proportions.

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In the compound AB
0.14 g of A are combined with `B = 0.16 g`
1.0 g of A are combined with `B=(0.16)/(0.14)g=1.143g`
In the compound AC
0.35 of A are combined with C = 0.05 g
1.0 g of A are combined with `C=(0.05)/(0.35)g=0.143 g`
Ratio by weight of B and C combined with 1.0 g of C in the two compounds `= (1.143)/(0.143)`
In the compound BC
Ratio by weight of B and C `= (2.2857)/(0.2857)`
Comparing (i) and (ii),
`(1.143)/(0.143):(2.2857)/(0.2857)or 8:8or 1:1`
This illustrates the Law of Reciprocal Proportions.
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