Verify the law of reciprocal proportions from the following data :
KCl contains 52.0 % potassium , KI contains 23.6 % potassium while Icl contains 78.2 % iodine.

Explanation

Let 1 g of potassium (K) be the fixed weight
In KCl, 52.0 g of K are combined with Cl = 48.0 g
1.0 g of K are combined with `Cl = (48.0)/(52.0)g = 0.092 g`
In KI, 23.6 g of K are combined with `I = 76.4 g`
1.0 g of K is combined with `I = (76.4)/(23.6)g = 3.24 g`
Ratio by weight of I and Cl combined with 1.0 g of K in the two halides `= (3.24)/(0.92)`
In ICI, ratio by weight of I and Cl `= (78.2)/(21.8)`
Comparing the two ratios :
`(3.24)/(0.92):(78.2)/(21.8)or 3.52:3.59`
Since the two ratios are nearly the same, this verifies the Law of Reciprocal Proportions.