How many atoms of fluorine are present in `1.9 xx 10^(-6)` gram of fluorine ? The atomic mass of fluroine is 19 amu.

Answer

`6.022 xx 10^(16)` atoms

Explanation

Gram atomic mass of fluorine = 19.0 g
19.0 gram of fluorine have atoms `= 6.022 xx 10^(23)`
`1.9 xx 10^(-6)` gram of fluorine have atoms `= (6.022xx10^(23)xx(1.9xx10^(-6)g))/((19.0g))=6.022xx10^(16)` atoms.