Calculate the mass of the following :
(i) 1 atom of carbon (ii) 1 atom of silver (iii) 1 molecule 1 benzene `(C_(6)H_(6))`
(iv) 1 molecule of water `(H_(2)O)`

Answer

(i) `1.99 xx 10^(-23)g` (ii) `1.79 xx 10^(-22) g` (iii) `1.295 xx 10^(22) g` (iv) `2.99 xx 10^(-23) g`

Explanation

(i) `6.022 xx 10^(23)` atoms of carbon have mass = 12.0 g
1.0 atom of carbon has mass `= (12.0)/(6.022xx10^(23))=1.99xx10^(-23)g`
(ii) `6.022 xx 10^(23)` atoms of silver have mass = 107.8 g
1.0 atom of silver has mass `= (107.8g)/(6.022xx10^(23))=1.79xx10^(-22)g`
(iii) `6.022 xx 10^(23)` molecules of benzene `(C_(6)H_(6))` have mass = 78.0 g
1.0 molecule of benzene `(C_(6)H_(6))` has mass `= (78.0g)/(6.022xx10^(23)) = 1.295 xx 10^(-22)g`
(iv) `6.022xx10^(23)` molecules of `H_(2)O` have mass = 18.0 g
1.0 molecule of `H_(2)O` has mass `= (18.0 g)/(6.022 xx 10^(23))=2.99 xx 10^(-23) g`.