Calculate the number atoms of oxygen present in 88 g of `CO_(2)` ? What would be the weight of CO having the same number of oxygen atoms ?

Explanation

44.0 grams of `CO_(2)` contain oxygen atoms `= 2 xx 6.022 xx 10^(23)` atoms
88.0 grams of `CO_(2)` contain oxygen atoms `= 2 xx 2 xx 6.022 xx 10^(23) = 2.41 xx 10^(24)` atoms
`6.022 xx 10^(23)` atoms of oxygen are present in `CO = 28.0g`
`2.41 xx 10^(24)` atoms of oxygen are present in `CO=(28.0xx2.41xx10^(24))/(6.022xx10^(23))=112.0g`.