Calculate the weight of carbon of monoxide having the same number of oxygen atoms as are present in 88 g of carbon dioxide.

Explanation

Step I. No of oxygen atoms in 88.0 of `CO_(2)`
44.0 g grams of `CO_(2)` have oxygen atoms `= 2 xx 6.022 xx 10^(23)`
`= 4 xx 6.022 xx 10^(23)`
Step II. Calculation of mass of CO
`6.022 xx 10^(23)` oxygen atoms are present in CO = 28.0 g
`4 xx 6.022 xx 10^(23)` oxygen atoms are present in `CO=28.0xx(4xx6.022xx10^(23))/(6.022xx10^(23))=112.0g`.