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1.7 g of an unknown gas occupies 2.24 L ...

1.7 g of an unknown gas occupies 2.24 L at N.T.P Calculate its molecular mass. Identify the gas.

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The correct Answer is:
17 g, Ammonia
2.24 L of the gas of N.T.P has mass = 1.7 g
22.4 L of the gas at N.T.P has mass `= ((1.7g))/((2.24L))xx(22.4L)=17g`
The molecular mass of gas `= 17 "g mol"^(-1)`
The gas is ammonia `(NH_(3))`
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