An organometallic compound on analysis gave the following results : `C = 64.4 %, H = 5.5 %, Fe = 29.9 %`. Determine the empirical formula.

Answer

`C_(10)H_(10)Fe`

Explanation

Empirical formula may be calculated as :
`{:("Element","Percentage","Atomic mass","Gram atoms (Moles)","Atomic ratio (Molar ratio)","Simplest whole no. ratio"),("C",64.4,12,(64.4)/(12)=5.4,(5.4)/(0.53)=10.2,10),("H",5.5,1,(5.5)/(1)=5.5,(5.5)/(0.53)=10.3,10),("Fe",29.9,56,(29.9)/(56)=0.53,(0.53)/(0.53)=1.0,1):}`
Empirical formula of the compound `= C_(10)H_(10)Fe`.