A Cylinder contains 0.32 g of oxygen. The same volume of an unknown gas 'X' under similar conditions of temperature and pressure weighs 0.26 g. The gas 'X' is known the contain only carbon and hydrogen atoms in the ratio 1 : 1. Identify the gas 'X'.

Answer

`C_(2)H_(2)`

Explanation

No. of moles of oxygen `(O_(2))` present in `0.32 g = ((0.32 g))/(("32 g mol"^(-1)))=0.1` mol
Volume of `O_(2)` corresponding to 0.1 mole = 2.24 L
Volume of unknown gas 'X' = 2.24 L
2.24 L of unknown gas 'X' weigh = 0.26 g
22.4 L of unknown gas 'X' weigh `= ((0.26g))/((2.24L))xx(22.4L)=26g`
Since the gas contains only carbon and hydrogen in the ratio 1 : 1 , its `C_(2)H_(2)` (Acetylene).