Four grams of copper chloride on analysis was found to contain 1.890 g of copper and 2.110 g of chlorine (Cl). What is the empirical formula of copper chloride ?

Answer

`CuCl_(2)`

Explanation

Step I. Percentage of the element
Percentage of `Cu=(1.89)/(4.0)xx100=47.25,` Percentage of `Cl =(2.11)/(4.0)xx100=52.75`
Step II. Empirical formula of copper chloride
`{:("Element","Percentage","Atomic mass","Gram atoms (Moles)","Atomic ratio (Molar ratio)","Simplest whole no. ratio"),("Cu",47.25,63.5,(47.25)/(63.5)=0.74,(0.74)/(0.74)=1,1),("Cl",52.75,35.5,(52.75)/(35.5)=1.48,(1.48)/(0.74)=2,2):}`
Empirical formula of the compound `= CuCl_(2)`.