An hourly requirement of an astronaut can be satisfied by the energy released when 34 grams of sucrose `(C_(12)H_(22)O_(11))` are burnt in his body. How many grams of oxygen would be require to carry in space capsule to meet his requirement for one day (24 hours) ?

Answer

916.2 g

Explanation

Step I. Mass of sucrose required
Mass of sucrose needed for 1 hour = 34 g
Mass of sucrose needed for 24 hours `= 34 xx 24 = 816 g`
Step II. Mass of oxygen required
`underset(underset(=342g)(12xx12+22xx1+16xx11))(C_(12)H_(22)O_(11))+underset(underset(=384g)(12xx32))(12O_(2))rarr12CO_(2)+11H_(2)O`
342 g of sucrose require oxygen = 384 g
816 g of sucrose require oxygen `= (384)/(342)xx816=916.2g`.