5.82 g of a silver coin is dissolved in ...

5.82 g of a silver coin is dissolved in nitric acid. One adding solution, all the silver present gets precipitated as AgCl. The weight of the precipitate is found to be 7.20 g. What is the percentage of silver in the coin ?

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The correct Answer is:

`93.1 %`

Weight of AgCl precipitated = 7.20 g
Weight of silver in the preciptate `= ((108g))/((143.50g))xx(7.20g)=5.42g`
Percentage of silver in the coin `= ((5.42g))/((5.83g))xx100=93.1%`.

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