0.5 mole of calcium carbonate id decomposed by an aqueous solution containing 25 % JCl by mass. Calculate the mass of the solution consumed.

Answer

146 g

Explanation

Chemical equation for the reaction is :
`underset("1 mol")(CaCO_(3))+underset("2 mol")(2HCl)rarrCaCl_(2)+H_(2)O+CO_(2)`
1 mole of `CaCO_(3)` react with HCl = 2 mol
0.5 mole of `CaCO_(3)` react with HCl = 1 mol = 36.5 g
Mass of HCl solution required ot consumed `= 36.5 xx (100)/(25) = 146 g`.