A sample of hydrochloric acid contains 20 % hydrochloric acid by weight. How much of this acid is required for the complete reduction of 50 g of calcium carbonate ?

Answer

182.5 g

Explanation

Chemical equation for the reaciton is :
`underset(underset(=100g)(40+12+48))(CaCO_(3))+underset(underset(=73g)(2(1+35.5)))(2HCl)rarrCaCl_(2)+H_(2)O+CO_(2)`
100 g of calcium carbonate require acid = 73 g
50 g of calcium carbonate require acid `= (73)/(100) xx 50 = 36.5 g`
Mass of the sample of hydrochloric `= 36.5 xx (100)/(20) = 182.5 g`.