Calculate the volume of carbon dioxide at N.T.P evolved by strong heating of 20 g of calcium carbonate.

Answer

4.48 L

Explanation

The balanced chemical equation is :
`underset(underset(100g)("1 mol"))(CaCO_(3))rarrunderset(underset("22.4 L at N.T.P")("1 mol"))(CaO+CO_(2))`
100 g of `CaCO_(3)` evolve carbon dioxide = 22.4 L
20 g of `CaCO_(3)` evolve carbon dioxide `= ((22.4 L))/((100g))xx(20g)=4.48L`.