Calculate the volume of oxygen at N.T.P that would be required to convert 5 litres of carbon monoxide into carbon dioxide.

Answer

2.5 L

Explanation

Chemicalm equation for the reaction is :
`underset(2L)(2CO(g))+underset(1L)(O_(2)(g))rarr2CO_(2)(g)`
2 of CO(g) require `O_(2)(g)` at N.T.P = 1L
5L of CO(g) require `O_(2)(g)` at N.T.P `= (5)/(2)=2.5 L`.