Calculate the amount of NaOH present in 200 mL of 0.5 N solution.

Answer

4 g

Explanation

Normality of solution (N) `= ("Mass of NaOH")/("Equivalent mass of NaOH"/("Volume of solution in mL"/1000))`
`("0.5 equiv L"^(-1))=(W)/(("40 g equiv"^(-1))xx("0.2 L"))`
`W=("0.5 equiv L"^(-1))xx("40 g equiv"^(-1))xx("0.2 L")=4g`.