How many moles and how many grams of sodium chloride are present in 250 mL of 0.5 M NaCl solution ?

Answer

0.125 mol, 7.3 g

Explanation

Molarity of solution (M) `= ("Moles of NaCl (n)")/("Volume of solution in mL"/(1000))`
`("0.5 mol L"^(-1))=(n)/(0.250L)`
`n =("0.5 mol L"^(-1)) xx (0.250 L) = 0.125` mol
`:.` No. of moles of NaCl = 0.125 mol
No. of grams of `NaCl=("0.125 mol")xx("58.5 g mol"^(-1))=7.3g`.