0.48 g of a sample of a compound containing boron and oxygen contains 0.192 g of boron and 0.288 g of oxygen. What is the percentage composition of the compound ?

Answer

B = 40 %, 0 = 60 %

Explanation

Mass of compound taken = 0.48 g
Mass of boron present = 0.192 g
Mass of oxygen present = 0.288 g
Percent of B `= (("0.192 g"))/(("0.48g"))xx100=40%`
Percentage of O `=(("0.288 g"))/(("0.48 g"))xx100=60%`.