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4.4 g of an unknown gas occupies 2.24 L ...

4.4 g of an unknown gas occupies 2.24 L of volume under N.T.P. conditions. The gas may be :

A

`CO_(2)`

B

CO

C

`O_(2)`

D

`SO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
2.24 L of gas correspond to mass = 4.4 g
22.4 L of gas correspond to mass `= (4.4)/(2.24) xx22.4`
`= 44.0 g`
The gas is `CO_(2)`.
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