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The weight of pure NaOH required to prep...

The weight of pure NaOH required to prepare 250 mL of 0.1 N solution is :

A

4 g

B

2 g

C

1 g

D

5 g

Text Solution

Verified by Experts

The correct Answer is:
C
`("0.1 Equiv. L"^(-1))=("Mass of NaOH")/(("40 g equiv")^(-1)xx("0.2 5L"))`
Mass of `NaOH = 0.1 xx 40 xx 0.25 =1g`.
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