10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in the reaction will be :

Options

A. 3 mol
B. 4 mol
C. 1 mol
D. 2 mol

Answer

B

Explanation

`underset("1 mol")(H_(2)(g))+underset("0.5 mol")(1//2O_(2)(g))rarrunderset("1 mol")(H_(2)O(l))`
10 gof `H_(2)=((10g))/(("2 g mol"^(-1)))=5` mol
64 g of `O_(2)=((64g))/(("32 g mol"^(-1)))=2` mol
In this reaction, `O_(2)` is limiting reactant 0.5 mol of oxygen from water = 1 mol
2 mol of oxygen from water
`= (("1 mol"))/(("0.5 mol"))xx("2 mol")=4` mol.