No. of moles in 100 mg of heptane is …………than those in 10 mg of propyne

Options

A. 4 times greater
B. 4 times lesser
C. 2.5 times greater
D. 2.5 times lesser

Answer

A

Explanation

No. of moles in 100 mg of heptane `(C_(7)H_(16))`
`= ((100xx10^(-3)g))/(("100g mol"^(-1)))=1xx10^(-3)`
No. of moles in 10 mg of propyne `(C_(3)H_(4))`
`= ((10xx10^(-3)g))/(("40 g mol"^(-1)))=(1)/(4)xx10^(-3)`
No. of moles of heptane are four times the no. of moles of propyne.