The equivalent mass of `MnSO_(4)` is half its molecular mass when it is converted to

Options

A. `Mn_(2)O_(3)`
B. `MnO_(2)`
C. `MnO_(4)^(-)`
D. `MnO_(4)^(2-)`

Answer

B

Explanation

The equivalent mass will be half the molecular mass when the change in 0.N of Mn is 2
In `MnSO_(4)` , O.N. of Mn = +2
In `Mn_(2)O_(3)` , O.N. of Mn = +3
In `MnO_(2)` , O.N of Mn = +4
In `MnO_(4)^(-)` , O.N of Mn = +7
In `MnO_(4)^(2-)` , O.N of Mn = +6
Thus, O.N. of Mn changes from +2 to +4 when `MnSO_(4)` is converted to `MnO_(2)`
`:.` (b) is the correct answer.