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Dissolving 120 g of urea (molecular mass...

Dissolving 120 g of urea (molecular mass = 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is :

A

1.78 M

B

2.00 M

C

2.05 M

D

2.22 M

Text Solution

Verified by Experts

The correct Answer is:
C
No. of moles of urea `= ("Mass of urea")/("Molar mass")`
`=((120g))/(("60 g mol"^(-1)))=2` mol
Mass of solution `= (1000+120)=1120`g
Volume of solution `= ("Mass of solution")/("Density of solution")`
`=((1120g))/(("1.15 g mL"^(-1)))=974mL`
`=0.974L`
Molarity of solution (M)
`= ("Moles of urea")/("Volume of solution in litres")`
`=(("2.0 mol"))/(("0.974 L))=2.05mol L^(-1)`.
`= 2.05 M`.
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